What is the inverse of f(x)=-sqrt(4-x^2) ?

The inverse of f(x)=-sqrt(4-x^2) is sqrt(-x^2+4),-sqrt(-x^2+4)

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inverse of f(x)=-sqrt(4-x^2)

inverse

f (x) = - 4 - x^{2}

- x^{2} + 4, - - x^{2} + 4

Solution steps

y = - 4 - x^{2}

Replace

x

with

y

x = - 4 - y^{2}

Solve for

y, x = - 4 - y^{2}

- x^{2} + 4, - - x^{2} + 4

f (x) = \frac{2 x}{x + 4}

ln (x^{2} + 1)

f (x) = \frac{x + 5}{x ^{2} - 16}

f (x) = \frac{x ^{2} + 3 x - 10}{x ^{2} - 4}

f (x) = \frac{3 x + 2}{x ^{2} - 7 x}

What is the inverse of f(x)=-sqrt(4-x^2) ?
The inverse of f(x)=-sqrt(4-x^2) is sqrt(-x^2+4),-sqrt(-x^2+4)