What is the domain of f(x)=sqrt(14x^2+14) ?

The domain of f(x)=sqrt(14x^2+14) is -infinity <x<infinity

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domain of f(x)=sqrt(14x^2+14)

domain

f (x) = 14 x^{2} + 14

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

x^{2} - 2 x - 11

\frac{3 - x}{x - 2}

f (x) = 3^{x}

f (x) = e^{4 x + 2}

(8, - 10), (2, - 5)

What is the domain of f(x)=sqrt(14x^2+14) ?
The domain of f(x)=sqrt(14x^2+14) is -infinity <x<infinity