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Popular >

midpoint (8,-10),(2,-5)

Solution

midpoint

(8, - 10), (2, - 5)

Solution

(5, - \frac{15}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (8, - 10), (x_{2}, y_{2}) = (2, - 5)

= (\frac{2 + 8}{2}, \frac{- 5 - 10}{2})

Refine

= (5, - \frac{15}{2})

Popular Examples

domain of f(x)=sqrt(x+4)+1 domain

f (x) = x + 4 + 1

inverse of 122 inverse

122

inverse of f(x)=(-15-2x)/3 inverse

f (x) = \frac{- 15 - 2 x}{3}

range of-1/2 x^2-2x+6 range

- \frac{1}{2} x^{2} - 2 x + 6

parallel y=-1/9 x+2,(3,1)parallel

y = - \frac{1}{9} x + 2, (3, 1)

Frequently Asked Questions (FAQ)

What is the midpoint (8,-10),(2,-5) ?
The midpoint (8,-10),(2,-5) is (5,-15/2)