What is the domain of f(x)=sqrt(x+4)+1 ?

The domain of f(x)=sqrt(x+4)+1 is x>=-4

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domain of f(x)=sqrt(x+4)+1

domain

f (x) = x + 4 + 1

x \geq - 4

Interval Notation

[- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

The function domain

x \geq - 4

122

f (x) = \frac{- 15 - 2 x}{3}

- \frac{1}{2} x^{2} - 2 x + 6

y = - \frac{1}{9} x + 2, (3, 1)

\frac{x}{2}

What is the domain of f(x)=sqrt(x+4)+1 ?
The domain of f(x)=sqrt(x+4)+1 is x>=-4