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Popular >

range of-1/2 x^2-2x+6

Solution

range

- \frac{1}{2} x^{2} - 2 x + 6

Solution

f (x) \leq 8

+1

Interval Notation

(- \infty, 8]

Solution steps

Vertex of

- \frac{1}{2} x^{2} - 2 x + 6 :

Maximum

(- 2, 8)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - \frac{1}{2},

Vertex

(x_{v}, y_{v}) = (- 2, 8)

f (x) \leq 8

Popular Examples

parallel y=-1/9 x+2,(3,1)parallel

y = - \frac{1}{9} x + 2, (3, 1)

domain of x/2 domain

\frac{x}{2}

inverse of f(x)=10-3x inverse

f (x) = 10 - 3 x

range of f(x)= 1/(x+7)range

f (x) = \frac{1}{x + 7}

domain of f(x)=8ln(x)-x^2 domain

f (x) = 8 ln (x) - x^{2}

Frequently Asked Questions (FAQ)

What is the range of-1/2 x^2-2x+6 ?
The range of-1/2 x^2-2x+6 is f(x)<= 8