What is the domain of (x/(x+8))/(x/(x+8)+8) ?

The domain of (x/(x+8))/(x/(x+8)+8) is x -64/9

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domain of (x/(x+8))/(x/(x+8)+8)

domain

\frac{\frac{x}{x + 8}}{\frac{x}{x + 8} + 8}

x < - 8 or - 8 < x < - \frac{64}{9} or x > - \frac{64}{9}

Interval Notation

(- \infty, - 8) \cup (- 8, - \frac{64}{9}) \cup (- \frac{64}{9}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{64}{9}, x = - 8

The function domain

x < - 8 or - 8 < x < - \frac{64}{9} or x > - \frac{64}{9}

x^{2} sin (\frac{1}{x})

f (x) = \frac{( 6 + x ^{4} )}{x ^{2} - x ^{4}}

f (x) = x^{2} - 4

f (x) = 9 x^{2} + 2 x^{3}

f (x) = \frac{4 x ^{4}}{2 x ^{2} - 3}

What is the domain of (x/(x+8))/(x/(x+8)+8) ?
The domain of (x/(x+8))/(x/(x+8)+8) is x<-8\lor-8<x<-64/9 \lor x>-64/9