What is the domain of f(x)=(sqrt(x+4))/(x-2) ?

The domain of f(x)=(sqrt(x+4))/(x-2) is -4 2

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domain of f(x)=(sqrt(x+4))/(x-2)

domain

f (x) = \frac{x + 4}{x - 2}

- 4 \leq x < 2 or x > 2

Interval Notation

[- 4, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

- 4 \leq x < 2 or x > 2

f (x) = \frac{x ^{3} - 2 x ^{2} - 3 x}{x - 3}

5 + (10 + x)^{\frac{1}{2}}

f (x) = \frac{( 5 x ^{2} - 3 )}{x + 2}

f (x) = \frac{5 + 2 ^{x}}{1 - 2 ^{x}}

f (x) = \frac{1}{x - 3}

What is the domain of f(x)=(sqrt(x+4))/(x-2) ?
The domain of f(x)=(sqrt(x+4))/(x-2) is -4<= x<2\lor x>2