What is the perpendicular 3x+12y=60,(-7,5) ?

The perpendicular 3x+12y=60,(-7,5) is y=4x+33

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perpendicular 3x+12y=60,(-7,5)

perpendicular

3 x + 12 y = 60, (- 7, 5)

y = 4 x + 33

Solution steps

Find the line

y = mx + b

perpendicular to

3 x + 12 y = 60

that passes through

(- 7, 5)

Find the slope of

3 x + 12 y = 60 : m = - \frac{1}{4}

Compute the slope of the perpendicular line:

m_{p} = 4

Find the line with slope m=

4

and passing through

(- 7, 5) : y = 4 x + 33

y = 4 x + 33

f (x) = \frac{8 x ^{2} + 1}{2 x ^{2} + 5 x - 3}

f (x) = \frac{( x - 3 ) ( x + 4 )}{x ^{2} - 4}

(x + 2) \cdot e^{\frac{1}{x}}

f (x) = (x - 3)^{3} + 1

f (x) = x^{2}

What is the perpendicular 3x+12y=60,(-7,5) ?
The perpendicular 3x+12y=60,(-7,5) is y=4x+33