What is the domain of f(x)=(sqrt(8-x))/(sqrt(x+8)) ?

The domain of f(x)=(sqrt(8-x))/(sqrt(x+8)) is -8<x<= 8

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domain of f(x)=(sqrt(8-x))/(sqrt(x+8))

domain

f (x) = \frac{8 - x}{x + 8}

- 8 < x \leq 8

Interval Notation

(- 8, 8]

Solution steps

Find non-negative values for radicals:

- 8 \leq x \leq 8

Find undefined (singularity) points:

x = - 8

Combine real regions and undefined points for final function domain

- 8 < x \leq 8

\frac{- 6 x + 12}{5 x - 10}

f (x) = \frac{x + 10}{x ^{2} - 100}

x = 9 (y - 7)^{2} + 5

f (x) = \frac{x + 2}{x - 6}

f (x) = - 0.1 t^{2} + 1.2 t + 98.3

What is the domain of f(x)=(sqrt(8-x))/(sqrt(x+8)) ?
The domain of f(x)=(sqrt(8-x))/(sqrt(x+8)) is -8<x<= 8