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Popular >

distance (0,-3),(6,-1)

Solution

distance

(0, - 3), (6, - 1)

Solution

210

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(0, - 3)

and

(6, - 1)

is

= (6 - 0)^{2} + (- 1 - (- 3))^{2}

Simplify

= 210

Popular Examples

domain of f(x)=6x-4 domain

f (x) = 6 x - 4

inverse of f(x)= 1/4 (1-x)inverse

f (x) = \frac{1}{4} (1 - x)

line (0,4),(0.00224,20)line

(0, 4), (0.00224, 20)

domain of x^2+3x-5 domain

x^{2} + 3 x - 5

perpendicular y= 8/3 x-2,(-8,-6)perpendicular

y = \frac{8}{3} x - 2, (- 8, - 6)

Frequently Asked Questions (FAQ)

What is the distance (0,-3),(6,-1) ?
The distance (0,-3),(6,-1) is 2sqrt(10)