What is the inverse of f(x)=sqrt(9-x^2) ?

The inverse of f(x)=sqrt(9-x^2) is sqrt(-x^2+9),-sqrt(-x^2+9)

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inverse of f(x)=sqrt(9-x^2)

inverse

f (x) = 9 - x^{2}

- x^{2} + 9, - - x^{2} + 9

Solution steps

y = 9 - x^{2}

Replace

x

with

y

x = 9 - y^{2}

Solve for

y, x = 9 - y^{2}

- x^{2} + 9, - - x^{2} + 9

f (x) = 3 x^{4} + 8 x^{3} + 4

f (x) = \frac{5}{( x - 4 ) ^{3}}

f (x) = x^{2} - 9 x

f (x) = \frac{x - 3}{x + 3}

f (x) = \frac{5 e ^{x}}{e ^{x} - 8}

What is the inverse of f(x)=sqrt(9-x^2) ?
The inverse of f(x)=sqrt(9-x^2) is sqrt(-x^2+9),-sqrt(-x^2+9)