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Popular >

extreme f(x)=x^2+7x+9

Solution

extreme points

f (x) = x^{2} + 7 x + 9

Solution

Minimum (- \frac{7}{2}, - \frac{13}{4})

Solution steps

f^{'} (x) = 2 x + 7

Find intervals:

Decreasing

: - \infty < x < - \frac{7}{2},

Increasing

: - \frac{7}{2} < x < \infty

Plug

x = - \frac{7}{2}

into

x^{2} + 7 x + 9 : - \frac{13}{4}

Minimum (- \frac{7}{2}, - \frac{13}{4})

Popular Examples

domain of (x+1)/(x^2-x-6)domain

\frac{x + 1}{x ^{2} - x - 6}

domain of ((3x^3-x^2-27x+9))/(x^2+4x+3)domain

\frac{( 3 x ^{3} - x ^{2} - 27 x + 9 )}{x ^{2} + 4 x + 3}

intercepts of f(x)=16-x^2 intercepts

f (x) = 16 - x^{2}

parallel x-y=-1 parallel

x - y = - 1

inverse of f(x)=10^{x/2}inverse

f (x) = 1 0^{\frac{x}{2}}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+7x+9 ?
The extreme f(x)=x^2+7x+9 is Minimum(-7/2 ,-13/4)