What is the extreme f(x)=x^3-7x^2+15x+9 ?

The extreme f(x)=x^3-7x^2+15x+9 is Maximum(5/3 , 518/27),Minimum(3,18)

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extreme f(x)=x^3-7x^2+15x+9

extreme points

f (x) = x^{3} - 7 x^{2} + 15 x + 9

Maximum (\frac{5}{3}, \frac{518}{27}), Minimum (3, 18)

Solution steps

f^{'} (x) = 3 x^{2} - 14 x + 15

Find intervals:

Increasing

: - \infty < x < \frac{5}{3},

Decreasing

: \frac{5}{3} < x < 3,

Increasing

: 3 < x < \infty

Plug

x = \frac{5}{3}

into

x^{3} - 7 x^{2} + 15 x + 9 : \frac{518}{27}

Maximum (\frac{5}{3}, \frac{518}{27})

Plug

x = 3

into

x^{3} - 7 x^{2} + 15 x + 9 : 18

Minimum (3, 18)

Maximum (\frac{5}{3}, \frac{518}{27}), Minimum (3, 18)

f (x) = \frac{x - 4}{x ^{2} + 13 x + 36}

f (x) = - 4 x + 7 y = 3

\frac{x ^{2}}{x}

f (x) = 4 - 25 - x^{2}

f (x) = - 6 x + 5

What is the extreme f(x)=x^3-7x^2+15x+9 ?
The extreme f(x)=x^3-7x^2+15x+9 is Maximum(5/3 , 518/27),Minimum(3,18)