What is the asymptotes of f(x)=(x-4)/(x^2+13x+36) ?

The asymptotes of f(x)=(x-4)/(x^2+13x+36) is Vertical: x=-9,x=-4,Horizontal: y=0

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asymptotes of f(x)=(x-4)/(x^2+13x+36)

asymptotes

f (x) = \frac{x - 4}{x ^{2} + 13 x + 36}

Vertical : x = - 9, x = - 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x - 4}{x ^{2} + 13 x + 36} : x = - 9, x = - 4

Horizontal Asymptotes of

\frac{x - 4}{x ^{2} + 13 x + 36} : y = 0

Slant Asymptotes of

\frac{x - 4}{x ^{2} + 13 x + 36} :

None

Vertical : x = - 9, x = - 4, Horizontal : y = 0

f (x) = - 4 x + 7 y = 3

\frac{x ^{2}}{x}

f (x) = 4 - 25 - x^{2}

f (x) = - 6 x + 5

f (x) = - 3 x^{2} - 2 x^{3}

What is the asymptotes of f(x)=(x-4)/(x^2+13x+36) ?
The asymptotes of f(x)=(x-4)/(x^2+13x+36) is Vertical: x=-9,x=-4,Horizontal: y=0