What is the extreme f(x)=-3x^2-2x^3 ?

The extreme f(x)=-3x^2-2x^3 is Minimum(-1,-1),Maximum(0,0)

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extreme f(x)=-3x^2-2x^3

extreme points

f (x) = - 3 x^{2} - 2 x^{3}

Minimum (- 1, - 1), Maximum (0, 0)

Solution steps

f^{'} (x) = - 6 x - 6 x^{2}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = - 1

into

- 3 x^{2} - 2 x^{3} : - 1

Minimum (- 1, - 1)

Plug

x = 0

into

- 3 x^{2} - 2 x^{3} : 0

Maximum (0, 0)

Minimum (- 1, - 1), Maximum (0, 0)

\frac{( x ^{3} + 1 )}{x ^{2} + 4 x}

(2, - 1), (10, 7)

\frac{e ^{x}}{1 + x}

f (x) = \frac{x ^{2} + 5 x - 6}{x + 3}

f (x) = 2 x^{2} - x - 1

What is the extreme f(x)=-3x^2-2x^3 ?
The extreme f(x)=-3x^2-2x^3 is Minimum(-1,-1),Maximum(0,0)