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Popular >

distance (1,3),(4,-3)

Solution

distance

(1, 3), (4, - 3)

Solution

35

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(1, 3)

and

(4, - 3)

is

= (4 - 1)^{2} + (- 3 - 3)^{2}

Simplify

= 35

Popular Examples

domain of f(x)= 1/(x^2+1)-1/(x^2-1)domain

f (x) = \frac{1}{x ^{2} + 1} - \frac{1}{x ^{2} - 1}

inverse of f(x)=x^{1/2}-7 inverse

f (x) = x^{\frac{1}{2}} - 7

periodicity of f(x)=-4cos(2/5 x)-2 periodicity

f (x) = - 4 cos (\frac{2}{5} x) - 2

inverse of f(x)=x+12 inverse

f (x) = x + 12

domain of 3x^3+2 domain

3 x^{3} + 2

Frequently Asked Questions (FAQ)

What is the distance (1,3),(4,-3) ?
The distance (1,3),(4,-3) is 3sqrt(5)