What is the domain of f(x)= 1/(x-4)+1/(6-x) ?

The domain of f(x)= 1/(x-4)+1/(6-x) is x 6

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domain of f(x)= 1/(x-4)+1/(6-x)

domain

f (x) = \frac{1}{x - 4} + \frac{1}{6 - x}

x < 4 or 4 < x < 6 or x > 6

Interval Notation

(- \infty, 4) \cup (4, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = 6

The function domain

x < 4 or 4 < x < 6 or x > 6

f (x) = - x^{3} - 3 x^{4}

2 x + y = 12

f (x) = \frac{( x + 1 )}{x ^{2} - 9}

f (x) = 4 + 4 + x

f (x) = - (4 x + 10 y) = - 9

What is the domain of f(x)= 1/(x-4)+1/(6-x) ?
The domain of f(x)= 1/(x-4)+1/(6-x) is x<4\lor 4<x<6\lor x>6