What is the domain of f(x)=3x^2+sqrt(x-2) ?

The domain of f(x)=3x^2+sqrt(x-2) is x>= 2

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domain of f(x)=3x^2+sqrt(x-2)

domain

f (x) = 3 x^{2} + x - 2

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

f (x) = 2 x + 1

f (x) = - \frac{2}{3} lo g_{10} (x - 1) + 2

f (x) = \frac{2 x + 3}{5}

f (x) = - \frac{1}{5} cos (\frac{1}{5} x)

(0.8) (5.3)

What is the domain of f(x)=3x^2+sqrt(x-2) ?
The domain of f(x)=3x^2+sqrt(x-2) is x>= 2