What is the inverse of f(x)=4(x+3)^2-16 ?

The inverse of f(x)=4(x+3)^2-16 is (sqrt(x+16))/2-3,-(sqrt(x+16))/2-3

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inverse of f(x)=4(x+3)^2-16

inverse

f (x) = 4 (x + 3)^{2} - 16

\frac{x + 16}{2} - 3, - \frac{x + 16}{2} - 3

Solution steps

y = 4 (x + 3)^{2} - 16

Replace

x

with

y

x = 4 (y + 3)^{2} - 16

Solve for

y, x = 4 (y + 3)^{2} - 16

\frac{x + 16}{2} - 3, - \frac{x + 16}{2} - 3

2 x - 3

x^{2} + 12

f (x) = x^{2} + 4 x + 5

f (x) = x^{9}

f (x) = 7 x^{2}

What is the inverse of f(x)=4(x+3)^2-16 ?
The inverse of f(x)=4(x+3)^2-16 is (sqrt(x+16))/2-3,-(sqrt(x+16))/2-3