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Popular >

extreme f(x)=x^2+4x+5

Solution

extreme points

f (x) = x^{2} + 4 x + 5

Solution

Minimum (- 2, 1)

Solution steps

f^{'} (x) = 2 x + 4

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

x^{2} + 4 x + 5 : 1

Minimum (- 2, 1)

Popular Examples

inverse of f(x)=x^9 inverse

f (x) = x^{9}

inverse of f(x)=7x^2 inverse

f (x) = 7 x^{2}

inverse of y=sqrt(4-x^2)inverse

y = 4 - x^{2}

extreme f(x)=5+3x^2 extreme points

f (x) = 5 + 3 x^{2}

distance (10,-3),(2,-4)distance

(10, - 3), (2, - 4)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+4x+5 ?
The extreme f(x)=x^2+4x+5 is Minimum(-2,1)