What is the inverse of y=sqrt(4-x^2) ?

The inverse of y=sqrt(4-x^2) is sqrt(-x^2+4),-sqrt(-x^2+4)

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inverse of y=sqrt(4-x^2)

inverse

y = 4 - x^{2}

- x^{2} + 4, - - x^{2} + 4

Solution steps

y = 4 - x^{2}

Replace

x

with

y

x = 4 - y^{2}

Solve for

y, x = 4 - y^{2}

- x^{2} + 4, - - x^{2} + 4

f (x) = 5 + 3 x^{2}

(10, - 3), (2, - 4)

- \frac{3}{2} x + y = 4

f (x) = \frac{4 ( x + 1 ) ( x - 2 )}{x ( x - 3 )}

\frac{x ^{2} - 1}{x ^{2} - 4}

What is the inverse of y=sqrt(4-x^2) ?
The inverse of y=sqrt(4-x^2) is sqrt(-x^2+4),-sqrt(-x^2+4)