What is the intercepts of f(x)=x^2+y^2+2x-4y+1=0 ?

The intercepts of f(x)=x^2+y^2+2x-4y+1=0 is Y Intercepts: (0,0)

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intercepts of f(x)=x^2+y^2+2x-4y+1=0

intercepts

f (x) = x^{2} + y^{2} + 2 x - 4 y + 1 = 0

Y Intercepts : (0, 0)

Solution steps

x -

axis interception points of

0 :

None

y -

axis interception point of

0 : (0, 0)

Y Intercepts : (0, 0)

f (x) = \frac{- 5}{x + 2}

f (x) = ln (x^{4} - 1)

f (x) = - x^{2} + 3 x + 7

y = x^{2} - 3

\frac{x + 21}{x - 7}

What is the intercepts of f(x)=x^2+y^2+2x-4y+1=0 ?
The intercepts of f(x)=x^2+y^2+2x-4y+1=0 is Y Intercepts: (0,0)