What is the range of f(x)=log_{2}(2^x) ?

The range of f(x)=log_{2}(2^x) is -infinity <f(x)<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=log_{2}(2^x)

range

f (x) = lo g_{2} (2^{x})

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

lo g_{2} (2^{x})

Inverse of

lo g_{2} (2^{x}) : x

x

Find the domain of each inverse function

Domain of

x : - \infty < x < \infty

Combine the intervals

- \infty < f (x) < \infty

f (x) = \frac{( 2 x + 1 )}{x - 3}

f (x) = \frac{5 x}{3 x ( x + 12 )}

f (x) = e^{6 x - 5}

f (x) = \frac{x ^{3} - 9 x}{3 x ^{2} - 6 x - 9}

f (x) = 5 x + (5 x - 6)

What is the range of f(x)=log_{2}(2^x) ?
The range of f(x)=log_{2}(2^x) is -infinity <f(x)<infinity