What is the critical (x^2-1)^3 ?

The critical (x^2-1)^3 is x=-1,x=0,x=1

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critical (x^2-1)^3

critical points

(x^{2} - 1)^{3}

x = - 1, x = 0, x = 1

Solution steps

(x^{2} - 1)^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 0, x = 1

Identify critical points not in

f (x)

domain

Domain of

(x^{2} - 1)^{3} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 0, x = 1

x^{2} e^{- 3 x}

f (x) = \frac{x}{4}

y - 5 x = 5

f (x) = x - 8

\frac{4 x ^{2} + 1}{x ^{2} + x + 16}