What is the domain of f(x)=x+ln(x^2-1) ?

The domain of f(x)=x+ln(x^2-1) is x 1

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domain of f(x)=x+ln(x^2-1)

domain

f (x) = x + ln (x^{2} - 1)

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 1

The function domain

x < - 1 or x > 1

f (x) = e^{x - 2}

f (x) = - 2 x + 4

x = - 1

(x - 3)^{8} (x + 5)^{6} (14 - 13 x)

f (x) = \frac{4}{( x - 3 ) ^{2}}

What is the domain of f(x)=x+ln(x^2-1) ?
The domain of f(x)=x+ln(x^2-1) is x<-1\lor x>1