What is the inverse of f(x)=sqrt(x^2+7x) ?

The inverse of f(x)=sqrt(x^2+7x) is (-7+sqrt(49+4x^2))/2 ,(-7-sqrt(49+4x^2))/2

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inverse of f(x)=sqrt(x^2+7x)

inverse

f (x) = x^{2} + 7 x

\frac{- 7 + 49 + 4 x ^{2}}{2}, \frac{- 7 - 49 + 4 x ^{2}}{2}

Solution steps

y = x^{2} + 7 x

Replace

x

with

y

x = y^{2} + 7 y

Solve for

y, x = y^{2} + 7 y

\frac{- 7 + 49 + 4 x ^{2}}{2}, \frac{- 7 - 49 + 4 x ^{2}}{2}

f (x) = \frac{4}{11 - 2 x}

3 - tan (\frac{x}{2} + \frac{π}{3})

f (x) = - 9 - x^{2}

f (x) = x^{2} - 72

f (x) = \frac{x}{4} + 7

What is the inverse of f(x)=sqrt(x^2+7x) ?
The inverse of f(x)=sqrt(x^2+7x) is (-7+sqrt(49+4x^2))/2 ,(-7-sqrt(49+4x^2))/2