What is the domain of f(x)=sqrt(x^2-72) ?

The domain of f(x)=sqrt(x^2-72) is x = 6sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x^2-72)

domain

f (x) = x^{2} - 72

x \leq - 62 or x \geq 62

Interval Notation

(- \infty, - 62] \cup [62, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 62 or x \geq 62

The function domain

x \leq - 62 or x \geq 62

f (x) = \frac{x}{4} + 7

f (x) = \frac{x}{x + 1}

f (x) = \frac{2 x + 5}{7 + x}

- x^{6} + 42 x^{5} - 42 x + 17

(4, 2), (0, 4)

What is the domain of f(x)=sqrt(x^2-72) ?
The domain of f(x)=sqrt(x^2-72) is x<=-6sqrt(2)\lor x>= 6sqrt(2)