What is the domain of f(x)=sqrt(x/(x+1)) ?

The domain of f(x)=sqrt(x/(x+1)) is x = 0

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domain of f(x)=sqrt(x/(x+1))

domain

f (x) = \frac{x}{x + 1}

x < - 1 or x \geq 0

Interval Notation

(- \infty, - 1) \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x < - 1 or x \geq 0

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x \geq 0

f (x) = \frac{2 x + 5}{7 + x}

- x^{6} + 42 x^{5} - 42 x + 17

(4, 2), (0, 4)

\frac{5 x}{7 x - 2}

\frac{x ^{2}}{x ^{2} + 3}

What is the domain of f(x)=sqrt(x/(x+1)) ?
The domain of f(x)=sqrt(x/(x+1)) is x<-1\lor x>= 0