What is the domain of h(x)=sqrt(x^2-9) ?

The domain of h(x)=sqrt(x^2-9) is x = 3

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domain of h(x)=sqrt(x^2-9)

domain

h (x) = x^{2} - 9

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

f (x) = \frac{x ^{2} + x}{- x ^{2} + 4 x}

f (x) = x^{2} + 3 x + 4

y = arctan (\frac{x - 1}{x + 1})

3 x - 2 y = 5

y = 5 x + 11, (- 1, 6)

What is the domain of h(x)=sqrt(x^2-9) ?
The domain of h(x)=sqrt(x^2-9) is x<=-3\lor x>= 3