What is the critical (4(x-1))/((x+1)(x-1)) ?

The critical (4(x-1))/((x+1)(x-1)) is None

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critical (4(x-1))/((x+1)(x-1))

critical points

\frac{4 ( x - 1 )}{( x + 1 ) ( x - 1 )}

None

Solution steps

\frac{4 ( x - 1 )}{( x + 1 ) ( x - 1 )}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{4 ( x - 1 )}{( x + 1 ) ( x - 1 )} : x < - 1 or - 1 < x < 1 or x > 1

\frac{4 ( x - 1 )}{( x + 1 ) ( x - 1 )}

is not defined at

x = - 1

, therefore:

None

(- 4, - 2), (- 3, - 5)

\frac{e ^{x}}{5 + e ^{x}}

(1 - x) (25 - x^{2})

2 - \frac{x}{x - 2}

f (x) = x^{2} + 3 x

What is the critical (4(x-1))/((x+1)(x-1)) ?
The critical (4(x-1))/((x+1)(x-1)) is None