What is the domain of f(x)=ln(x+sqrt(x^2+1)) ?

The domain of f(x)=ln(x+sqrt(x^2+1)) is -infinity <x<infinity

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domain of f(x)=ln(x+sqrt(x^2+1))

domain

f (x) = ln (x + x^{2} + 1)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{4 x - 20}{x - 5}

3 x - 2 y = 12

2 x^{2} - 5

f (x) = \frac{- x ^{2} + 4 x - 3}{2 - x}

f (x) = x e^{- 3 x}

What is the domain of f(x)=ln(x+sqrt(x^2+1)) ?
The domain of f(x)=ln(x+sqrt(x^2+1)) is -infinity <x<infinity