What is the parity y=(2x^2-3x+1)/(sqrt(3x^4+4x^2+2)) ?

The parity y=(2x^2-3x+1)/(sqrt(3x^4+4x^2+2)) is Neither even nor odd

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

parity y=(2x^2-3x+1)/(sqrt(3x^4+4x^2+2))

parity

y = \frac{2 x ^{2} - 3 x + 1}{3 x ^{4} + 4 x ^{2} + 2}

Neither even nor odd

Solution steps

f (x) : \frac{2 x ^{2}}{3 x ^{4} + 4 x ^{2} + 2} - \frac{3 x}{3 x ^{4} + 4 x ^{2} + 2} + \frac{1}{3 x ^{4} + 4 x ^{2} + 2}

f (- x) : \frac{2 x ^{2}}{2 + 4 x ^{2} + 3 x ^{4}} + \frac{3 x}{2 + 4 x ^{2} + 3 x ^{4}} + \frac{1}{2 + 4 x ^{2} + 3 x ^{4}}

- f (x) : - \frac{2 x ^{2}}{2 + 4 x ^{2} + 3 x ^{4}} + \frac{3 x}{2 + 4 x ^{2} + 3 x ^{4}} - \frac{1}{2 + 4 x ^{2} + 3 x ^{4}}

Check parity of

\frac{2 x ^{2}}{3 x ^{4} + 4 x ^{2} + 2} - \frac{3 x}{3 x ^{4} + 4 x ^{2} + 2} + \frac{1}{3 x ^{4} + 4 x ^{2} + 2}

Check if Even:

False

Check if Odd:

False

Neither even nor odd

3 x - 9

x^{3} - 3 x

f (x) = \frac{x + 2}{x + 8}

y = \frac{1}{2} x + 1, (1, 4)

f (x) = \frac{9}{x + 4}

What is the parity y=(2x^2-3x+1)/(sqrt(3x^4+4x^2+2)) ?
The parity y=(2x^2-3x+1)/(sqrt(3x^4+4x^2+2)) is Neither even nor odd