What is the domain of f(x)= 9/(sqrt(x+4)) ?

The domain of f(x)= 9/(sqrt(x+4)) is x>-4

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domain of f(x)= 9/(sqrt(x+4))

domain

f (x) = \frac{9}{x + 4}

x > - 4

Interval Notation

(- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

Find undefined (singularity) points:

x = - 4

Combine real regions and undefined points for final function domain

x > - 4

2 x^{2} - 3 x + 6

f (x) = \frac{x ^{2} - 9}{x ^{2} + 4 x - 21}

- 1 - 4 cos (2 x)

f (x) = (x + 3)^{2} - 4

f (x) = x^{2} - 16

What is the domain of f(x)= 9/(sqrt(x+4)) ?
The domain of f(x)= 9/(sqrt(x+4)) is x>-4