What is the domain of f(x)=sqrt(x^2-16) ?

The domain of f(x)=sqrt(x^2-16) is x = 4

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domain of f(x)=sqrt(x^2-16)

domain

f (x) = x^{2} - 16

x \leq - 4 or x \geq 4

Interval Notation

(- \infty, - 4] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

The function domain

x \leq - 4 or x \geq 4

4 x + 7 y = 4 y - 7

(5, - 1), (10, - 0.6)

cos (6 x)

f (x) = \frac{8 x + 36}{10 x - 5}

f (x) = 2 - lo g_{3} (x - 1)

What is the domain of f(x)=sqrt(x^2-16) ?
The domain of f(x)=sqrt(x^2-16) is x<=-4\lor x>= 4