What is the inverse of f(x)=2-log_{3}(x-1) ?

The inverse of f(x)=2-log_{3}(x-1) is 3^{2-x}+1

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inverse of f(x)=2-log_{3}(x-1)

inverse

f (x) = 2 - lo g_{3} (x - 1)

3^{2 - x} + 1

Solution steps

y = 2 - lo g_{3} (x - 1)

Replace

x

with

y

x = 2 - lo g_{3} (y - 1)

Solve for

y, x = 2 - lo g_{3} (y - 1)

3^{2 - x} + 1

y = 1.5 ln (x + 5)

f (x) = \frac{17}{1 + 7 ^{- t}}

f (x) = x x + 3

f (x) = \frac{3 x}{8 + x}

f (x) = x^{2} - 8 x - 15

What is the inverse of f(x)=2-log_{3}(x-1) ?
The inverse of f(x)=2-log_{3}(x-1) is 3^{2-x}+1