What is the inverse of f(x)=((x-7))/((x+3)) ?

The inverse of f(x)=((x-7))/((x+3)) is (-7-3x)/(x-1)

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inverse of f(x)=((x-7))/((x+3))

inverse

f (x) = \frac{( x - 7 )}{( x + 3 )}

\frac{- 7 - 3 x}{x - 1}

Solution steps

y = \frac{x - 7}{x + 3}

Replace

x

with

y

x = \frac{y - 7}{y + 3}

Solve for

y, x = \frac{y - 7}{y + 3}

\frac{- 7 - 3 x}{x - 1}

f (x) = \frac{- 16 + n}{4}

f (x) = - x - 7

y = \frac{3}{4} x - 3

y - x = - 5

What is the inverse of f(x)=((x-7))/((x+3)) ?
The inverse of f(x)=((x-7))/((x+3)) is (-7-3x)/(x-1)