What is the critical f(x)=xe^{-4x} ?

The critical f(x)=xe^{-4x} is x= 1/4

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critical f(x)=xe^{-4x}

critical points

f (x) = x e^{- 4 x}

x = \frac{1}{4}

Solution steps

x e^{- 4 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{4}

Identify critical points not in

f (x)

domain

Domain of

x e^{- 4 x} : - \infty < x < \infty

All critical points are in domain

x = \frac{1}{4}

f (x) = 6 x^{4} + 8 x^{3}

y = \frac{2 x ^{3} + 2}{x ^{2}}

f (x) = \frac{x ^{3} + 1}{x ^{2}}

f (x) = (x^{3} + 8)^{5}

\frac{x ^{3}}{x ^{2} + 1}