What is the inverse of f(x)=(x^3+8)^5 ?

The inverse of f(x)=(x^3+8)^5 is cube root of \sqrt[5]{x}-8

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inverse of f(x)=(x^3+8)^5

inverse

f (x) = (x^{3} + 8)^{5}

Solution steps

y = (x^{3} + 8)^{5}

Replace

x

with

y

x = (y^{3} + 8)^{5}

Solve for

y, x = (y^{3} + 8)^{5}

\frac{x ^{3}}{x ^{2} + 1}

f (x) = 5 x - 4

y = - 2 (x - 3)^{2} + 1

y = x^{2} + 4 x + 4

f (x) = x

What is the inverse of f(x)=(x^3+8)^5 ?
The inverse of f(x)=(x^3+8)^5 is cube root of \sqrt[5]{x}-8