What is the range of f(x)=2sqrt(x+3)+5 ?

The range of f(x)=2sqrt(x+3)+5 is f(x)>= 5

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range of f(x)=2sqrt(x+3)+5

range

f (x) = 2 x + 3 + 5

f (x) \geq 5

Interval Notation

[5, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 5

f (x) \geq 5

3 x^{4} + 4 x^{3}

arctan (\frac{x - 1}{x + 1})

x^{2}

f (x) = 4 x^{2} + 1

What is the range of f(x)=2sqrt(x+3)+5 ?
The range of f(x)=2sqrt(x+3)+5 is f(x)>= 5