What is the domain of ((x+4))/(x^2-9) ?

The domain of ((x+4))/(x^2-9) is x 3

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domain of ((x+4))/(x^2-9)

domain

\frac{( x + 4 )}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = y^{2} = x + 9

f (x) = \frac{2 x ^{2} - 5 x + 5}{x - 2}

y = \frac{1}{x - 3} + 2

y = \frac{2 x + 3}{x ( x + 1 )}

f (x) = \frac{5 x}{3}

What is the domain of ((x+4))/(x^2-9) ?
The domain of ((x+4))/(x^2-9) is x<-3\lor-3<x<3\lor x>3