What is the range of y= 1/(x-3)+2 ?

The range of y= 1/(x-3)+2 is f(x) 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of y= 1/(x-3)+2

range

y = \frac{1}{x - 3} + 2

f (x) < 2 or f (x) > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{1}{x - 3} + 2

Inverse of

\frac{1}{x - 3} + 2 : \frac{3 x - 5}{x - 2}

\frac{3 x - 5}{x - 2}

Find the domain of each inverse function

Domain of

\frac{3 x - 5}{x - 2} : x < 2 or x > 2

Combine the intervals

f (x) < 2 or f (x) > 2

y = \frac{2 x + 3}{x ( x + 1 )}

f (x) = \frac{5 x}{3}

\frac{1}{3} sin (- 4 x)

f (x) = 6 x + 1

(8, 6), (0, - 3)

What is the range of y= 1/(x-3)+2 ?
The range of y= 1/(x-3)+2 is f(x)<2\lor f(x)>2