What is the extreme f(x)=2x^5+5x^4-15 ?

The extreme f(x)=2x^5+5x^4-15 is Maximum(-2,1),Minimum(0,-15)

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extreme f(x)=2x^5+5x^4-15

extreme points

f (x) = 2 x^{5} + 5 x^{4} - 15

Maximum (- 2, 1), Minimum (0, - 15)

Solution steps

f^{'} (x) = 10 x^{4} + 20 x^{3}

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 2

into

2 x^{5} + 5 x^{4} - 15 : 1

Maximum (- 2, 1)

Plug

x = 0

into

2 x^{5} + 5 x^{4} - 15 : - 15

Minimum (0, - 15)

Maximum (- 2, 1), Minimum (0, - 15)

f (x) = \frac{x - 1}{( x + 3 ) ( x - 1 )}

(5, - 2), (- 7, 3)

f (x) = \frac{24 x ^{2} + 6 x}{2 x + 1}

f (x) = x^{2} + 2 x - 15

f (x) = x^{2} - 4 x

What is the extreme f(x)=2x^5+5x^4-15 ?
The extreme f(x)=2x^5+5x^4-15 is Maximum(-2,1),Minimum(0,-15)