What is the asymptotes of f(x)=(24x^2+6x)/(2x+1) ?

The asymptotes of f(x)=(24x^2+6x)/(2x+1) is Vertical: x=-1/2 ,Slant: y=12x-3

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asymptotes of f(x)=(24x^2+6x)/(2x+1)

asymptotes

f (x) = \frac{24 x ^{2} + 6 x}{2 x + 1}

Vertical : x = - \frac{1}{2}, Slant : y = 12 x - 3

Solution steps

Vertical asymptotes of

\frac{24 x ^{2} + 6 x}{2 x + 1} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{24 x ^{2} + 6 x}{2 x + 1} :

None

Slant Asymptotes of

\frac{24 x ^{2} + 6 x}{2 x + 1} : y = 12 x - 3

Vertical : x = - \frac{1}{2}, Slant : y = 12 x - 3

f (x) = x^{2} + 2 x - 15

f (x) = x^{2} - 4 x

(9.6), (3.3)

f (x) = \frac{\frac{3}{x}}{\frac{3}{x} + 3}

f (x) = 3^{x + 1} - 1

What is the asymptotes of f(x)=(24x^2+6x)/(2x+1) ?
The asymptotes of f(x)=(24x^2+6x)/(2x+1) is Vertical: x=-1/2 ,Slant: y=12x-3