What is the range of f(x)=3^{x+1}-1 ?

The range of f(x)=3^{x+1}-1 is f(x)>-1

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range of f(x)=3^{x+1}-1

range

f (x) = 3^{x + 1} - 1

f (x) > - 1

Interval Notation

(- 1, \infty)

Solution steps

The range of an exponential function of the form

c \cdot n^{a x + b} + k

f (x) > k

k = - 1

f (x) > - 1

\frac{5 - 2 x}{6 x + 3}

4 x + 7 + 5

f (x) = - \frac{1}{x + 4} - 1

f (x) = \frac{6}{2 + e ^{x}}

f (x) = \frac{x ^{2} - x - 2}{x ^{2} - 5 x + 6}