What is the inverse of 4sqrt(x+7)+5 ?

The inverse of 4sqrt(x+7)+5 is (x^2+25}{16}-\frac{5x)/8-7

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inverse of 4sqrt(x+7)+5

inverse

4 x + 7 + 5

\frac{x ^{2} + 25}{16} - \frac{5 x}{8} - 7

Solution steps

y = 4 x + 7 + 5

Replace

x

with

y

x = 4 y + 7 + 5

Solve for

y, x = 4 y + 7 + 5

\frac{x ^{2} + 25}{16} - \frac{5 x}{8} - 7

f (x) = - \frac{1}{x + 4} - 1

f (x) = \frac{6}{2 + e ^{x}}

f (x) = \frac{x ^{2} - x - 2}{x ^{2} - 5 x + 6}

f (x) = \frac{1}{4} x^{2} - 1

m = 8 b = 3

What is the inverse of 4sqrt(x+7)+5 ?
The inverse of 4sqrt(x+7)+5 is (x^2+25}{16}-\frac{5x)/8-7