What is the critical y=(x^2-4x)^2 ?

The critical y=(x^2-4x)^2 is x=0,x=2,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical y=(x^2-4x)^2

critical points

y = (x^{2} - 4 x)^{2}

x = 0, x = 2, x = 4

Solution steps

(x^{2} - 4 x)^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 2, x = 4

Identify critical points not in

f (x)

domain

Domain of

(x^{2} - 4 x)^{2} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 2, x = 4

f (x) = - 1.25 x^{2} + 50 x + 4000

\frac{x + 1}{x - 3}

f (x) = 5 - 12 x

\frac{x ^{3}}{x ^{2} + 1}

f (x) = (x - 2)^{2} (x - 1)