What is the domain of f(x)=sqrt(x^2-36) ?

The domain of f(x)=sqrt(x^2-36) is x = 6

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domain of f(x)=sqrt(x^2-36)

domain

f (x) = x^{2} - 36

x \leq - 6 or x \geq 6

Interval Notation

(- \infty, - 6] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 6 or x \geq 6

The function domain

x \leq - 6 or x \geq 6

\frac{1}{x} - 2

f (x) = x^{2} - 9

2 x - 3 y = 6

f (x) = (x - 1)^{2}, x \geq 1

\frac{9 x - 8}{3}

What is the domain of f(x)=sqrt(x^2-36) ?
The domain of f(x)=sqrt(x^2-36) is x<=-6\lor x>= 6