What is the inverse of f(x)=(3x-4)/(4x+9) ?

The inverse of f(x)=(3x-4)/(4x+9) is (-4-9x)/(4x-3)

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inverse of f(x)=(3x-4)/(4x+9)

inverse

f (x) = \frac{3 x - 4}{4 x + 9}

\frac{- 4 - 9 x}{4 x - 3}

Solution steps

y = \frac{3 x - 4}{4 x + 9}

Replace

x

with

y

x = \frac{3 y - 4}{4 y + 9}

Solve for

y, x = \frac{3 y - 4}{4 y + 9}

\frac{- 4 - 9 x}{4 x - 3}

y - 4 = 6 (x + 7)

f (x) = \frac{e ^{x - 1}}{( x - 1 ) ^{2}}

8 x - 4 y = 3

y = cos (x - \frac{7 π}{2})

f (x) = \frac{x ^{2}}{x ^{2} - 4 x - 12}

What is the inverse of f(x)=(3x-4)/(4x+9) ?
The inverse of f(x)=(3x-4)/(4x+9) is (-4-9x)/(4x-3)