What is the shift y=cos(x-(7pi)/2) ?

The shift y=cos(x-(7pi)/2) is Phase:(7pi)/2 , Vertical:0

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shift y=cos(x-(7pi)/2)

shift

y = cos (x - \frac{7 π}{2})

Phase : \frac{7 π}{2}, Vertical : 0

Solution steps

f (x) = cos (x - \frac{7 π}{2})

g (B x - C) = cos (x - \frac{7 π}{2}), B = 1, C = \frac{7 π}{2}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{7 π}{2}}{1}

\frac{7 π}{2}

The vertical shift

D

0

0

f (x) = \frac{x ^{2}}{x ^{2} - 4 x - 12}

\frac{6 x ^{2} + x - 6}{x ^{2} - 1}

f (x) = \frac{( x - 2 )}{x + 2}

\frac{8 - x ^{3}}{2 x ^{2}}

(4, - 4), (- 6, - 4)

What is the shift y=cos(x-(7pi)/2) ?
The shift y=cos(x-(7pi)/2) is Phase:(7pi)/2 , Vertical:0