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Popular >

distance (1,-6),(-1,-3)

Solution

distance

(1, - 6), (- 1, - 3)

Solution

13

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(1, - 6)

and

(- 1, - 3)

is

= (- 1 - 1)^{2} + (- 3 - (- 6))^{2}

Simplify

= 13

Popular Examples

intercepts of f(x)=x^2+3x-10 intercepts

f (x) = x^{2} + 3 x - 10

inflection 3x^4-24x^3+48x^2 inflection points

3 x^{4} - 24 x^{3} + 48 x^{2}

midpoint (6,-7),(6,3)midpoint

(6, - 7), (6, 3)

domain of y=(2x-3)/(12-|x-12|)domain

y = \frac{2 x - 3}{12 - ∣ x - 12 ∣}

extreme t^2+2t-48 extreme points

t^{2} + 2 t - 48

Frequently Asked Questions (FAQ)

What is the distance (1,-6),(-1,-3) ?
The distance (1,-6),(-1,-3) is square root of 13